3^2x-4(3x)+27=0

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Solution for 3^2x-4(3x)+27=0 equation: 



3^2x-4(3x)+27=0

We add all the numbers together, and all the variables

-43x+3^2x+27=0

We move all terms containing x to the left, all other terms to the right

-43x+3^2x=-27

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